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4.9t^2=2.5t
We move all terms to the left:
4.9t^2-(2.5t)=0
We add all the numbers together, and all the variables
4.9t^2-(+2.5t)=0
We get rid of parentheses
4.9t^2-2.5t=0
a = 4.9; b = -2.5; c = 0;
Δ = b2-4ac
Δ = -2.52-4·4.9·0
Δ = 6.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.5)-\sqrt{6.25}}{2*4.9}=\frac{2.5-\sqrt{6.25}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.5)+\sqrt{6.25}}{2*4.9}=\frac{2.5+\sqrt{6.25}}{9.8} $
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